To double the exposure to the image receptor initially set at 5 mAs and 50 kVp, what kVp is required?

To determine the appropriate kVp that would double the exposure to the image receptor, it's important to understand the relationship between mAs and kVp in radiography.

When the exposure is doubled through kVp adjustments, a general rule of thumb is that increasing the kVp by about 15% can approximately double the exposure of the image receptor. This principle arises from the fact that increasing kVp increases both the penetration and quantity of photons reaching the receptor, leading to a higher exposure.

Starting with an initial setting of 50 kVp, a 15% increase would be calculated as follows:

15% of 50 kVp = 0.15 * 50 = 7.5

Adding this increase to the original kVp gives:

50 kVp + 7.5 kVp = 57.5 kVp

Since kVp must be rounded to practical settings in a clinical context, we can round 57.5 kVp to the nearest practical value, which is typically 58 kVp in radiographic settings. Therefore, setting the kVp to 58 would effectively double the exposure that was initially set at 5 mAs and 50 kVp.

Consequently, the option of 58 kVp aligns with the